Ignoring friction loss, if a water main at 50 psi supplies a flush-valve toilet located 50 feet above, how much pressure is available to operate the fixture?
AnswerSince 50ft x 0.434 lbf/sqin/ft (loss in static head) = 21.7 psi, then 50 psi - 21.7 psi = 28.3 psi
ARE 4.0 exam prep: BS
AnswerSince 50ft x 0.434 lbf/sqin/ft (loss in static head) = 21.7 psi, then 50 psi - 21.7 psi = 28.3 psi
ARE 4.0 exam prep: BS
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